codingForumsFTW
11-01-2009, 06:09 PM
ok this is the javascript
<script type="text/javascript">
var options = {
script:"test.php?json=true&limit=6&one="+document.getElementById('oneone').value,
//script:"test.php?json=true&limit=6&",
varname:"input",
json:true,
shownoresults:false,
maxresults:6,
callback: function (obj) { document.getElementById('testid').value = obj.id; },
};
var as_json = new bsn.AutoSuggest('testinput', options);
</script>
ok now no with this code not commented out i get
script:"test.php?json=true&limit=6&one="+document.getElementById('oneone').value,
i get the value of oneone in firebug test.php?json=true&limit=6&one=s_city
when i comment that out and put in
script:"test.php?json=true&limit=6&",
i get test.php?json=true&limit=6& varname=input
what i am asking is i know (well i think)i need a & in the first little section of code so i keeps adding the var name to the url .
please help thanks
<script type="text/javascript">
var options = {
script:"test.php?json=true&limit=6&one="+document.getElementById('oneone').value,
//script:"test.php?json=true&limit=6&",
varname:"input",
json:true,
shownoresults:false,
maxresults:6,
callback: function (obj) { document.getElementById('testid').value = obj.id; },
};
var as_json = new bsn.AutoSuggest('testinput', options);
</script>
ok now no with this code not commented out i get
script:"test.php?json=true&limit=6&one="+document.getElementById('oneone').value,
i get the value of oneone in firebug test.php?json=true&limit=6&one=s_city
when i comment that out and put in
script:"test.php?json=true&limit=6&",
i get test.php?json=true&limit=6& varname=input
what i am asking is i know (well i think)i need a & in the first little section of code so i keeps adding the var name to the url .
please help thanks