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View Full Version : select div in a row



c0mrade
09-10-2009, 12:08 AM
Hiya all, I'm really stuck .. here is my html :


<!-- Beginning of ROW !-->
<div id="row1">
<div class="entry">
free
<span>some text</span>
<p>DKK</p>
<input type="radio" name="row<?php echo $counter?>" id="radio" value="0" />

</div>

<div class="entry">
week
<span></span>
<p>DKK</p>
<input type="radio" name="row<?php echo $counter?>" id="radio2" value="75" />
</div>
</div>
<!-- End of ROW !-->
<!-- Beginning of ROW !-->
<div id="row2">
.... same as in row 1
</div>
<!-- End of ROW !-->
nth row ..


here is Jquery



$("input").click(function() {
$("input").parent("div").css("background", "url(images/div_bg.png)");
$(this).parent("div").css("background", "url(images/div_bg_hover.png)");
});



What I'm trying to do .. is when I select a radio input the div in which it is located should change background and it works perfectly if there is only one row, but for instance if I try to select the value in first row then I select value in second row.. the div in second row where radio input is located changes background as it should but the div in first row reverse itself to other background although input remained checked .. here is what I'm trying to achieve
http://i26.tinypic.com/34ythlj.png

And here is what I achieve :

http://i31.tinypic.com/24pweau.jpg

Fumigator
09-10-2009, 01:09 AM
This:


$("input").parent("div").css("background", "url(images/div_bg.png)");


Is setting the background image of every div that contains an input tag. You call that function every time an input is clicked on.



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