correct syntax

Having trouble getting the correct syntax on this script to work example below,


$display_stream = '<li><a href="', $link[1], '" title="', $stream, '">Stream</a><br />', "\n";
//$display_stream = "<li><a href=$link[1] title=$stream />Stream</a><br />"; - working but only displays 1 url link rather than all links on page
//echo '<li><a href="', $link[1], '" title="', $stream, '">Stream</a><br />', "\n"; - original function

You can't use commas when building a string like that. Commas are only applicable when using echo.

$display_stream = '<li><a href="' . $link[1] . '" title="' . $stream . '">Stream</a><br />' . "\n";

You can't use commas when building a string like that. Commas are only applicable when using echo.

$display_stream = '<li><a href="' . $link[1] . '" title="' . $stream . '">Stream</a><br />' . "\n";

That bugs me so much, I wish that it would be removed. I hate that the echo (and only echo), will accept multiple parameters.
That said, I'm a print formatter, so I'd go with the sprintf route:

$display_stream = sprintf('<li><a href="%s" title="%s">Stream</a></li>' . PHP_EOL, $link[1], $stream);

I've never thought to use that method in PHP - I only do it in C.