check if two variables are different

hi
i need to check if two variables are diffrent.
hopefully in the same way an if statment can check if two variables are the same with

if ($var1 == $var2);

can i just put an ! in front of one or something.

thanks

I assume you mean the value of the variables?

if ($var1 != $var2) // Or the less used: $var1 <> $var2


Techincally you should probably be able to wrap the whole works with a !.

if (!($var1 == $var2))

That should also work, but doesn't really make a lot of sense to me.

This would show if variables are different without type check:

if ($var1 != $var2)

I mean integer 5 and string "5" would be considered as equal.

This would show if variables are different with type check:

if ($var1 !== $var2)

In this case integer 5 and string "5" would be considered as not equal.

if($var1 != $var2) {

You only use a singe = rather with the ! than ==.

if($var1 != $var2) {

You only use a singe = rather with the ! than ==.

No thats not correct. != is typeless, !== is typed, just like == is typeless and === is typed.
So 5 == '5' is true, but 5 === '5' is not.

thanks
it works.

i have been confused by this concept for long time.. thanks any way