Explanation of Code

Hi,
I'm new to coding so I apologize in advance if my questions are basic.

I wrote this basic piece of code but frankly I don't understand what is actually happening

#(Script 1)

print "What is your name?\n";
chomp($name = <STDIN>); #waits for user input from keyboard
print ("$name" & 'name');

Here's the executed code
Process started >>>
John Doe
What is your name?
Jahd<<< Process finished.

I'm trying to learn by experimentation and I was wondering if anyone could explain why the output is Jahd. What exactly is the computer doing?
Thanks,
Canyon289

print ("$name" & 'name');

Jahd<<< Process finished.

What exactly is the computer doing?


It's only doing what you asked it to do. Ever heard of "garbage in - garbage out"? :D

By using the ampersand in the print function, you're telling it to print the "bitwise AND (http://en.wikipedia.org/wiki/Bitwise_operation)" of the input string and the string 'name'. As I understand it, when applied to strings, it operates on the character codes.

this line:

print ("$name" & 'name');

is the same as:

print $name & 'name';

your use of parenthesis and quotes is just confusing the issue to you. As already pointed out, & is a perl operator. If you wanted to print a string you should have done this:

print "$name & 'name'";

If thats not what you wanted to do then you have to let us know what your intention was.

Thank you for both of your replies, it clears up my question.

To KevinADC
I'm trying to learn by experimentation and errors. Most of the time I can see where I made a mistake and how it affected the output but in this case I had no idea what was happening. But now I know it's a bitwise operation
Thank you so much for the explanations