Hello I am new to using Javascript and have been trying to incorporate this equation into my if statement but cannot get it to calculate properly no matter which method I use. Here is the function as I have it worked out presently.


function Points()
{
Rating = document.Arena.Rating.value;
{
if (Rating <= 1500){
returnValue = Math.round((0.22 * Rating + 14) * 0.76)
};
else {
returnValue = Math.round(1511.26 / (1 + 1639.28 * 2.71828 ^ (-0.00412 * Rating)) * 0.76)
};
document.Arena.Points2.value = returnValue
}
{
if (Rating <= 1500){
returnValue = Math.round((0.22 * Rating + 14) * 0.88)
};
else {
returnValue = Math.round(1511.26 / (1 + 1639.28 * 2.71828 ^ (-0.00412 * Rating)) * 0.88)
};
document.Arena.Points3.value = returnValue
}
{
if (Rating <= 1500){
returnValue = Math.round(0.22 * Rating + 14)
};
else {
returnValue = Math.round(1511.26 / (1 + 1639.28 * 2.71828 ^(-0.00412 * Rating))
};
document.Arena.Points5.value = returnValue
}
}


Now the problem I am having is in the else statement with the equation not executing correctly and giving a value of "0" since I am rounding. With the current equation and with a "Rating" of 1600 the "returnValue" should equal 465, but that is never the case. If I use Math.pow:


{
if (Rating <= 1500){
returnValue = Math.round(0.22 * Rating + 14)
};
else {
returnValue = Math.round(1511.26 / (Math.pow((1 + 1639.28 * 2.71828),(-0.00412 * Rating)))
};
document.Arena.Points5.value = returnValue
}


The result is 1.7133353971544615e+27 when again it should be 465. I know I'm missing something simple but with my lack of knowledge of javascript I'm just not seeing it.

Also I should note that this current project is a javascript conversion of my VB project I had made. Where the exponential value of (-0.00412 * Rating) is noted by the "^" and then executed as an exponential value. The result is the same in all of the else statements but for simplicity I singled out the last one as an example.

Thank You in advance for any help that can be given.

JB

The reason the first one returns 0 is not that you are rounding, but that "^" isn't the power operator in javascript but the bitwise XOR.

The second one does exactly what you tell it to do, so if you where expecting 465 but getting 10^27, your equation is just horribly wrong.

Please describe in words what you are trying to accomplish.

Edit: Oh, I didn't really compare those two versions before. You completely changed it up! Just change it to the way it was before, but using Math.pow:
returnValue = Math.round(1511.26 / (1 + 1639.28 * Math.pow(2.71828, (-0.00412 * Rating))));

Oh, and you're missing a right paren on all those else equations.

You are putting your semicolons in the wrong places.

But I don't think that's your big problem.

Yes, you must use Math.pow( number, power )

When I use Math.pow(1 + 1639.28 * 2.71828, -0.00412 * Rating ) that results in a very very tiny number, and so the results are always just 1511.26.

Could you maybe show us the formula in *math* terms, instead of in code?

Or show the VB code?

The js code doesn't match the VB -- misinterpretation of precedence and/or misplaced parenthesis. TryMath.round( 1511.26 / ( 1+ 1639.28 * Math.exp( -0.00412 * n)))

Too slow...

LOL! So this is homework you are both working on???

Or you just recognize the formula??

Nice catch, in any case, Shannon.

So simplifying the code a lot:

<script>
function Points()
{
var form = document.Arena;
var Rating = form.Rating.value;

var powerFactor = 1 + 1639.28 * Math.exp( -0.00412 * Rating )
var ratingFactor = 0.22 * Rating + 14;

var lower = (Rating <= 1500)

form.Points2.value = Math.round( lower ? ratingFactor * 0.76 : 1511.26 / (powerFactor * 0.76) );
form.Points3.value = Math.round( lower ? ratingFactor * 0.88 : 1511.26 / (powerFactor * 0.88) );
form.Points5.value = Math.round( lower ? ratingFactor : 1511.26 / powerFactor );
}
</script>

<form name="Arena">
<input name="Rating" onchange="Points()">
<hr>
Points2: <input name="Points2"><br/>
Points3: <input name="Points3"><br/>
Points5: <input name="Points5"><br/>
</form>


And, yes, for a Rating of 1600, Points5 is then 465.

Sure hope this was NOT homework.

LOL! So this is homework you are both working on???

Sure hope this was NOT homework.

The reason the first one returns 0 is not that you are rounding, but that "^" isn't the power operator in javascript but the bitwise XOR.

The second one does exactly what you tell it to do, so if you where expecting 465 but getting 10^27, your equation is just horribly wrong.

Please describe in words what you are trying to accomplish.

Edit: Oh, I didn't really compare those two versions before. You completely changed it up! Just change it to the way it was before, but using Math.pow:
returnValue = Math.round(1511.26 / (1 + 1639.28 * Math.pow(2.71828, (-0.00412 * Rating))));

Oh, and you're missing a right paren on all those else equations.

To Old Pedant, no this isn't homework but like I said earlier something I'm trying to convert to Javascript from VB to learn the coding better so I figured given I have made the program in VB it would help me to learn by doing something familiar.

To venegal, thank you for the simple solution that was my growing headache. I knew I had to use Math.pow() it was just the placement within the equation that was the big issue it seems and was my initial problem.

I would like to thank everyone that had responded to the thread and the great ideas presented. I really appreciate the feedback and the help.

Thank You again,
JB :D

Math.pow() is *NOT* the right answer.

And if you used the ^ operator in VB, *that* was not the right answer.

Math.exp() in JavaScript is the equivalent of the EXP( ) function in VB, which is what you should have been using.

Mind you, it probably doesn't make any practical difference whether you use EXP(x) or 2.718281828 ^ x, but the former will run just a bit faster.

If you weren't aware of it, A^B is calculated as EXP( B * LOG(A) ). So when you do 2.71828 ^ x you are really doing EXP( x * LOG(2.71828) ) which is EXP( x * 1 ) and so is EXP(x). But you forced the computer to do any extra LOG calculation and an extra multiply.