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View Full Version : Best way for a banning script



chrisvmarle
07-09-2002, 01:47 PM
Does anyone have a good banning script?

For now I'm using this is lots of my (test) scripts:

@BANNED_IP=("127.0.0.1","10.0.0","45");
$visitors_ip = $ENV{REMOTE_ADDR};
foreach (@BANNED_IP) {
if ($visitors_ip =~ /^$_/i) {
&nice_die("$banned_message");
}
}

But, I'm sure there's a much better way, since this script goes through all the IPs in @BANNED_IP and takes some time to execute if the list gets longer.

I hope I'm clear to you ;)

Thanks in advance;
Mzzl, Chris

Mouldy_Goat
07-09-2002, 04:00 PM
Are you sure it'll take that long to go through...?

Just as a test... on my machine it took under a second pretty much to loop through 1 000 000 values in an array and compare them to a number. I doubt you'll want to ban that many users hehe :).

The script I used was this by the way:

#!/usr/bin/perl

for ($i = 0; $i < 1000000; $i++) {
push (@numbers, int rand 1000);
}

$bftime = time();
print "Starting...\n";
foreach (@numbers) {
if (/^387$/) {
print "found one...\n";
}
}
$aftime = time();

print "Done..\n";
print "Time taken was: ", $aftime - $bftime, " seconds\n";

I think the way you've got of doing it will work just fine...

Mouldy_Goat
07-09-2002, 04:04 PM
On the other hand my machine is a 1.2Ghz Athlon... ;).

chrisvmarle
07-09-2002, 04:46 PM
But isn't there just a function to check if a value is in an array; for example:

I have a value $my_favorite containing fish and I have an array @food containing ("bread","apple","steak","patatoos","fish","icecream","vegitebles") (I don't know how to write some, but I hope you get the idea)
Now lets say the function I'm talking about is named where_is() and I use the next line:
$position = where_is($food,$my_favorite);
Then I want $position to be 4

Get it?

Thanks, Chris

Forgot a [/b]

Mouldy_Goat
07-10-2002, 01:14 AM
Nope, nothing like that... you'd have to make your own function, something like:


sub where_is {
my ($array, $what) = @_;
my ($i);

for ($i = 0; $i < scalar @$array; $i++) {
return $i if $what =~ /^$$array[$i]$/;
}

return -1;
}

That's assuming you're passing an array reference to the subroutine, rather than the array itself... i.e you'd call it with

print where_is (\@food, $my_favourite);

Rather than

print where_is (@food, $my_favourite);

Seriously - don't worry about your code - it's quite a common thing to do, really, and it really does use up less CPU time than you might think.

Perl isn't like PHP where there's a function for anything and everything, it gives you what you need language-wise, and you do the rest :)

chrisvmarle
07-10-2002, 11:40 AM
Ok, so there's no function what does what the function you made does...

Well, then I'll start using yours, thank you very much.

Mzzl, Chris

P.S. what does scalar do and why is the $ after ^ at /^$$array[$i]$/

Mouldy_Goat
07-10-2002, 01:49 PM
The 'scalar' forces the array to be interpreted in a scalar context - i.e. it returns the number of elements in the array. With arrays you can often use $#array to return the last element in the array, but I was uncertain about using this on an array reference.

The regular expression /^$$array[$i]$/ isn't too bad.

The ^ at the front and the $ at the end make sure it's an exact match. There are two $'s before 'array', because $array isn't a real array at all, it's actually something which merely refers to the @array, so in order to actually retrieve any values from it, it has to be dereferenced, and you can do this by prepending a $. (You can also do $array->[$i] I think).

Hope that helps a bit.

chrisvmarle
07-10-2002, 01:55 PM
Well, english isn't my primairy language, but I'll just read over it a couple of times and hope that's make me understand it.

Thanks a lot for all help

Mouldy_Goat
07-10-2002, 02:06 PM
Hmm yeah, my explanation wasn't great....

It might not be much easier in terms of reading - but this (http://www.perldoc.com/perl5.6.1/pod/perlreftut.html) will be more complete than anything I produce, and could help clear things up for you. I took a while to get the hang of references myself..

chrisvmarle
07-10-2002, 03:48 PM
That URL made most of it clear ;)

It even made me able to solve an other problem I gave up on :p

You've been :thumbsup: (great)

Thanks



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