View Full Version : adding value from dropdown or textfield to one database field

04-17-2009, 06:02 PM
Please have a look to the attachment to see what im trying to do.
Database field= "Age"
i want that if a user choose date of birth or if he writes his age in text box, the data goes to the fieldname 'Age ' only

how do i do this?

$insert = mysql_query("insert into register (Name,Gender,DOB,Age,TOB,POB) values ('".$_SESSION['Name']."', '".$_SESSION['Gender']."', '".$_SESSION['DateofBirth']."', '".$_SESSION['Age']."', '".$_SESSION['Timeofbirth']."', '".$_SESSION['Placeofbirth']."')

or die("Could not insert data because ".mysql_error());
im a newbie to php/mysql
please help!

04-17-2009, 06:17 PM
BBCode syntax highlighter shows a syntax error(missing quotes) in your above posted code.

04-17-2009, 06:20 PM
please gimme the solution

04-17-2009, 07:49 PM
As abduraooft said, look at what you posted and you'll see the error. He even told you what it was (a missing quote).

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