jasonc310771
03-21-2009, 12:25 PM
read web content via a weblink like
http://www.site.com/?id=123
what is the correct way to do this?
http://www.site.com/?id=123
what is the correct way to do this?
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read webpage content in to a variablejasonc310771 03-21-2009, 12:25 PM read web content via a weblink like http://www.site.com/?id=123 what is the correct way to do this? NeoPuma 03-21-2009, 12:37 PM You could do it like this: <?php $file = "http://www.example.com"; $handle = fopen($file, "r"); $contents = ''; while (!feof($handle)) { $contents .= fread($handle, 8192); } fclose($handle); // $contents will now contain the contents of the file ?> It's not been tested, but try it? I've basically pulled it from the PHP manual. timgolding 03-21-2009, 01:37 PM The only problem with doing it this way is you want to get the filesize of the file to read to tell the fread() (http://uk.php.net/manual/en/function.fread.php) function the size of file. Like so $contents .= fread($handle, filesize($file)); However filesize() (http://uk.php.net/manual/en/function.filesize.php) doesn't work on files that are not hosted on the same server that the script is running on. For instance i can get $filesize("my_file.txt") if my_file.txt is hosted on my server, but I can't get $filesize("http://www.example.com") A better way to do this is using the file_get_contents() (http://uk.php.net/manual/en/function.file-get-contents.php) function. Does the same thing but doesn't require to know the size of the file and is smaller code :) <?PHP $contents=''; $contents.=file_get_contents("http://www.example.com"); echo $contents; ?> |
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