MySQL SELECT Wont Run?!!?

<?php
$url = $_SERVER['REQUEST_URI'];
$split = preg_split('/\//', $url);

mysql_connect("mysql.xxxxxxxxx.com", "xxxxxxxxx", "xxxxxxxxx");
mysql_select_db("branchr");

$user = mysql_query("SELECT * FROM social_trees WHERE username = '$split[1]'");
$branches = mysql_query("SELECT * FROM network_branches WHERE user = '$split[1]'");

$row = mysql_fetch_array($user);

$u = $split[1];
?>


<?php echo $row['username']; ?> >>

<?php
while($row1 = mysql_fetch_array($branches)) {

$brnch = $row1['id'];
$url = $row1['network_feed'];
$net = $row1['network'];

$ch = curl_init($url);

curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_HEADER, 0);

$data = curl_exec($ch);
curl_close($ch);

$doc = new SimpleXmlElement($data, LIBXML_NOCDATA);
function parseRSS($xml, $u, $net, $brnch)
{

$cnt = count($xml->channel->item);
for($i=0; $i<$cnt; $i++)
{
$url = $xml->channel->item[$i]->link;
$title = $xml->channel->item[$i]->title;
$desc = $xml->channel->item[$i]->description;
$date = $xml->channel->item[$i]->pubDate;

// But this doesnt
$isitthere = mysql_query("SELECT * FROM `data` WHERE data.title = '$title' AND data.date = '$date' AND data.user = '$u'");
$counter = 0;

while($isrow = mysql_fetch_array($isitthere)) {
$counter ++;
}

if($counter == '0') {
// The code below runs!
mysql_query("INSERT INTO data VALUES ( NULL, '$title', '$desc', '$date', '$u', '$net', '$brnch' )");

}
}
}


if(isset($doc->channel))
{
parseRSS($doc, $u, $net, $brnch);
}


}
?>

See code comments for where it is, basically the bottom SQL executes but the top one doesn't. I get the following error:
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /home/.zusa/christianowens/branchr.com/user.php on line 50

$user = mysql_query("SELECT * FROM social_trees WHERE username = '".$split[1]."' ");
$branches = mysql_query("SELECT * FROM network_branches WHERE user = '".$split[1]."' ");

$isitthere = mysql_query("SELECT * FROM `data` WHERE data.title = '".$title."' AND data.date = '".$date."' AND data.user = '".$u."'");


try that

Same errors,

Here is the updated code with your suggestion:

<?php
$url = $_SERVER['REQUEST_URI'];
$split = preg_split('/\//', $url);

mysql_connect("xxxxxxxxxxxxxxxxxx", "xxxxxx", "xxxxxx");
mysql_select_db("branchr");

$user = mysql_query("SELECT * FROM social_trees WHERE username = '".$split[1]."' ");
$branches = mysql_query("SELECT * FROM network_branches WHERE user = '".$split[1]."' ");

$row = mysql_fetch_array($user);

$u = $split[1];
?>


<?php echo $row['username']; ?> >>

<?php
while($row1 = mysql_fetch_array($branches)) {

$brnch = $row1['id'];
$url = $row1['network_feed'];
$net = $row1['network'];

$ch = curl_init($url);

curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_HEADER, 0);

$data = curl_exec($ch);
curl_close($ch);

$doc = new SimpleXmlElement($data, LIBXML_NOCDATA);
function parseRSS($xml, $u, $net, $brnch)
{

$cnt = count($xml->channel->item);
for($i=0; $i<$cnt; $i++)
{
$url = $xml->channel->item[$i]->link;
$title = $xml->channel->item[$i]->title;
$desc = $xml->channel->item[$i]->description;
$date = $xml->channel->item[$i]->pubDate;

$isitthere = mysql_query("SELECT * FROM `data` WHERE data.title = '".$title."' AND data.date = '".$date."' AND data.user = '".$u."'");
$counter = 0;

while($isrow = mysql_fetch_array($isitthere)) {
$counter ++;
}

if($counter == '0') {

mysql_query("INSERT INTO data VALUES ( NULL, '$title', '$desc', '$date', '$u', '$net', '$brnch' )");

}
}
}


if(isset($doc->channel))
{
parseRSS($doc, $u, $net, $brnch);
}


}
?>

Could it be that it's inside a function? I don't see how, because the one below is working...

None of your mysql_ statements have any error checking logic to get them to tell you if they failed or not and why they failed.

move the function out side of the while loop too surprised it isn't erroring on redeclaring function

Oh my god, I am an idiot.

addslashes();

If your least post is referring to escaping data put into a query, addslashes() does not escape all the special characters that can break a query. Use mysql_real_escape_string()