jarv
08-07-2008, 09:23 AM
<img src="http://chart.apis.google.com/chart?cht=p3&chd=t:<?php echo "," $country['country_count'] ?>&chs=280x100&chl=<?php echo "|" $country['country'] ?>" />
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Parse error: syntax error, unexpected T_VARIABLE, expecting ',' or ';'jarv 08-07-2008, 09:23 AM <img src="http://chart.apis.google.com/chart?cht=p3&chd=t:<?php echo "," $country['country_count'] ?>&chs=280x100&chl=<?php echo "|" $country['country'] ?>" /> Iszak 08-07-2008, 09:31 AM <?php echo "," $country['country_count'] ?> <?php echo "|" $country['country'] ?> to <?php echo ",".$country['country_count'] ?> <?php echo "|".$country['country'] ?> djm0219 08-07-2008, 09:31 AM <img src="http://chart.apis.google.com/chart?cht=p3&chd=t:<?php echo "," . $country['country_count']; ?>&chs=280x100&chl=<?php echo "|" . $country['country']; ?>" /> You were missing closing semi-colons as well as the concatenation character between the first part of your echo and the variable. oesxyl 08-07-2008, 09:42 AM <img src="http://chart.apis.google.com/chart?cht=p3&chd=t:<?php echo "," $country['country_count'] ?>&chs=280x100&chl=<?php echo "|" $country['country'] ?>" /> I don't want to be rude but I sugest you to start from here: http://www.php.net/manual/en/langref.php at least basic things you must know if you want to use php. best regards |
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