dprichard
07-18-2008, 04:44 PM
I am trying to do an update that isn't working and was wondering how I could echo the query back out onto the page so I can see what it is actually saying. I tried this, but it didn't work.
if(isset($_POST['simulate']) && $_POST['simulate'] == 99) {
$todaysdate = '';
$todaysdate = mysql_real_escape_string($_POST['todaysdate']);
$updatequery = mysql_query("UPDATE EmployeeTimeOff SET CurrentAccrualAmount = (CurrentAccrualAmount + AccrualRate) WHERE NextAccrualDate = '$todaysdate' AND EmployeeId = '1'") or die(mysql_error());
echo $updatequery;
}
if(isset($_POST['simulate']) && $_POST['simulate'] == 99) {
$todaysdate = '';
$todaysdate = mysql_real_escape_string($_POST['todaysdate']);
$updatequery = mysql_query("UPDATE EmployeeTimeOff SET CurrentAccrualAmount = (CurrentAccrualAmount + AccrualRate) WHERE NextAccrualDate = '$todaysdate' AND EmployeeId = '1'") or die(mysql_error());
echo $updatequery;
}