...

View Full Version : problem positioning..



absolut
05-11-2008, 04:50 AM
database structure
http://img236.imageshack.us/img236/4026/ctableiy5.th.jpg (http://img236.imageshack.us/my.php?image=ctableiy5.jpg)

it should display this

http://img247.imageshack.us/img247/1179/38751214ys8.th.jpg (http://img247.imageshack.us/my.php?image=38751214ys8.jpg)



<?php
echo'<form method="post" name="myform" action="file.php">';
$result = mysql_query("SELECT iqid, cost, userid FROM ctable where postid=$post");
while ($row = mysql_fetch_array($result))
{
$arr[$row['iqid']][$row['userid']] = $row['cost'];
$uid[] = $row['userid'];
}
$uid = array_unique($uid);
$qid = array_keys($arr);
echo '<table cellpadding=5><tr><td></td>';
foreach($uid as $userid) echo "<td>$userid</td>";
echo '</tr>';
foreach($qid as $iqid)
{
echo "<tr><td>$iqid</td>";
foreach($uid as $userid)
{
echo '<td>';
if (isset($arr[$iqid][$userid])) echo $arr[$iqid][$userid];
echo '</td>';
}
}
$result = mysql_query("SELECT cid FROM ctable WHERE postid=$post");
while ($row = mysql_fetch_array($result))
{
echo "<input type='checkbox' name='sa[]' value='$row[cid]'>";
}
echo "</tr>";
echo '</table>';
echo '<input type="submit" name="listing" />';
echo'</form>';

?>
I've added checkbox and I need to get the cid..
I have problem in positioning, the checkbox appeared in the top of the userid(above userid)
I want the checkbox to appear beside with the cost..
please help me...

abduraooft
05-11-2008, 01:30 PM
How about changing your echo like

echo "<td><input type='checkbox' name='sa[]' value='$row[cid]'></td>";

absolut
05-12-2008, 01:17 AM
How about changing your echo like

echo "<td><input type='checkbox' name='sa[]' value='$row[cid]'></td>";
the output:
cost cost checkbox checkbox
cost cost checkbox checkbox
cost cost checkbox checkbox

I want to appear the checkbox beside with each cost
cost checkbox cost checkbox
cost checkbox cost checkbox
cost checkbox cost checkbox



EZ Archive Ads Plugin for vBulletin Copyright 2006 Computer Help Forum