displaying a page via a php include with a var....

[sir pannels]

hmm hey there...
the subject there.. is this ok in php.. so like..

<?
$page = $view
?>

<? include ('$page.php'); ?>

and the $view is cuming from the url string... cuz it says "faile dto open $page.php" yadda yadda.
any ideas?
thanks :D

[Nightfire]

Try $_GET['view'] or $HTTP_GET_VARS['view'] instead of $view

Also give include($page.'.php'); a try

[Ökii]

for security, always hardcode part of the path to the file into the include call whenever you are using url passed page names.

include('pages/'.$_GET['page'].'.php');

stops people running external scripts and exploring your file system and files.

[sir pannels]

ok cheers the both o fyou i`ll try it out now :)
P :thumbsup:

[brothercake]

As I understand it, variables inside strings are only allowed if you use double quotes. so


include ("$page.php");


or


include ("path/$page.php");



should work