2nd part of code is ignored

Calling the this function from "form99", which is located on another page.

The code:

function resultChooser(form99){
if (form99.searchstring != "")
{
form99.action="searchBool.php";
}
else
{
form99.action="searchBool_all.php";
}
}

I know the function is being acted upon. But only the first half of the If... Else statement seems to be recognized.

The default value of the textfield is null. So it should call the "searchBool_all.php" page if nothing is entered into the textfield.

Form code:

<form method="POST" name="form99" onsubmit="resultChooser(this);">
<table>
<tr>
<td>Searching by:</td>
<td>Insert search criteria. (Leave blank to view all records.)</td>
</tr>
<tr>
<td>Course title</td>
<td><input type="text" name="searchstring" value=""></td>
</tr>
</table>
<div style="position: absolute; left: 60px; top: 80px; width:255px;>
<input type="submit" value="Submit" name="B1">
<input type="reset" value="Reset" name="B2">
</div>
</form>

form99.searchstring.value is the value. The other is the object reference.

Please correct me if I'm wrong. I think I'm interpreting this correctly.

//function name referencing "form99"
function resultChooser(form99){

//Checking the value of searchstring which is located in form99
if (form99.searchstring != "")

//If a value ISN'T equal to null goto object - searchBool.php
{
form99.action="searchBool.php";
}

//If a value IS equal to null goto object - searchBool_all.php
else
{
form99.action="searchBool_all.php";
}
}

More like...


function resultChooser(form99){
if (form99.searchstring.value != "")
{
form99.action="searchBool.php";
}
else
{
form99.action="searchBool_all.php";
}
}

oh drat.

Thanks again!