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  1. #1
    New Coder
    Join Date
    May 2012
    Posts
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    Thanked 1 Time in 1 Post

    Ajax form only submits every other time

    Hi guys,

    Hoping someone can help as this is getting me really frustrated!

    I have a form that gets submitted via AJAX if the validation fails the form will be redisplayed with error messages.

    It works fine the first time, but on the second attempt it submits to the standard form and not the ajax request.

    JS code:-
    Code:
    $(document).ready(function() {
    $("#register").submit(function() {
    
        var str = $(this).serialize();
    
            $.ajax({
                type: "POST",
                url: "/my/register.php",
                data: str,
                success: function(msg) {
    
                    $(document).ajaxSubmit(function(event, request, settings) {
    					
                    result = msg;
    
    				$("#register").hide();
                    $("#registerBox").html(result).slideDown("slow");
                    $("#registerBox").html(result);
                    });
    
                }
    
            });
        return false;
        });
    });
    PHP script:-
    Code:
    <?php
    function showRegistration($error,$email){
    echo $error;
    if($error == "1"){
    	$emailInput = "<input type=\"email\" name=\"email\" class=\"inputerror\" />";
    }
    else
    {
    	$emailInput = "<input type=\"email\" name=\"email\" value=\"".$email."\" />";
    }
    if($error == "2"){
    	$passwordInput = "<input type=\"password\" name=\"password\" class=\"inputerror\" />";
    }
    else
    {
    	$passwordInput = "<input type=\"password\" name=\"password\" />";
    }
    if($error == "3"){
    	$passwordCheckInput = "<input type=\"password\" name=\"passwordcheck\" class=\"inputerror\" />";
    }
    else
    {
    	$passwordCheckInput = "<input type=\"password\" name=\"passwordcheck\" />";
    }
    if($error == "4"){
    	$passwordInput = "<input type=\"password\" name=\"password\" class=\"inputerror\" />";
    	$passwordCheckInput = "<input type=\"password\" name=\"passwordcheck\" class=\"inputerror\" />";
    }
    else
    {
    	$passwordInput = "<input type=\"password\" name=\"password\" />";
    	$passwordCheckInput = "<input type=\"password\" name=\"passwordcheck\" />";
    }
    else
    $registrationForm = <<<FORM
    <form class="register" action="#" method="post" name="register" id="register" >
    
    <ul>
    	<li><h2>Register</h2></li>
        <li>
            <label for="email">Email Address</label>
            $emailInput
    		</li>
        <li>
        	<label for="password">Password</label>
    		$passwordInput
    	</li>
    	<li>
        	<label for="passwordcheck">Re-Enter Password</label>
    		$passwordCheckInput
        </li>
    	</form>
    	<li>
        <button class="submit" type="submit" id="submit">Register</button>
    </li>
    </ul>
    
    FORM;
    echo $registrationForm;
    }
    ?>
    Thanks in advance for any help anyone can provide.

    Thanks
    Last edited by probi; 11-30-2013 at 02:58 PM.

  • #2
    Senior Coder DanInMa's Avatar
    Join Date
    Nov 2010
    Location
    Salem,Ma
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    Thanked 248 Times in 248 Posts
    try this and get rid of that ajaxsubmit junk.

    Code:
    $(document).ready(function() {
    $("#register").submit(function(e) {
      e.preventDefault();
        var str = $(this).serialize();
    
            $.ajax({
                type: "POST",
                url: "/my/register.php",
                data: str,
                success: function(msg) {
    
    		$("#register").hide();
                    $("#registerBox").html(msg).slideDown("slow");
                }
            });
        });
    });

  • #3
    Supreme Master coder! glenngv's Avatar
    Join Date
    Jun 2002
    Location
    Philippines
    Posts
    11,043
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    0
    Thanked 251 Times in 247 Posts
    You replace the DOM for the form with a new one, so the event that is bound to the form is lost.

    Try replacing this:

    Code:
    $("#register").submit(function() {
    with:

    Code:
    $(document).on("submit", "#register", function() {


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