I would just like to shorten my httprequest code so I will not create 3 variables(xmlhttp) & 3 PHP files.

Here's my ajax Code:
Code:
function showStudInfo(str)
{
	if(window.XMLHttpRequest)
     {
       xmlhttp = new XMLHttpRequest();
	   xmlhttp2 = new XMLHttpRequest();
	   xmlhttp3 = new XMLHttpRequest();
     }
     else
     {
       xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
	   xmlhttp2 = new ActiveXObject("Microsoft.XMLHTTP");
	   xmlhttp3 = new ActiveXObject("Microsoft.XMLHTTP");
     }
     xmlhttp.onreadystatechange=function()
     {
       if(xmlhttp.readyState==4 && xmlhttp.status==200)
       {
          document.form1.fname.value = xmlhttp.responseText;
       }
     }
	 xmlhttp2.onreadystatechange=function()
     {
       if(xmlhttp2.readyState==4 && xmlhttp2.status==200)
       {
          document.form1.lname.value = xmlhttp2.responseText;
       }
     }
	 xmlhttp3.onreadystatechange=function()
     {
       if(xmlhttp3.readyState==4 && xmlhttp3.status==200)
       {
          document.form1.course.value = xmlhttp3.responseText;
       }
     }
     xmlhttp.open("GET","php/incident-showfname.php?studnum="+str,true);
	 xmlhttp2.open("GET","php/incident-showlname.php?studnum="+str,true);
	 xmlhttp3.open("GET","php/incident-showcourse.php?studnum="+str,true);
	 xmlhttp.send();
	 xmlhttp2.send();
	 xmlhttp3.send();	
}
here's my PHP Code:
PHP Code:
<?php
$q
=$_GET["studnum"];

  
$host// Host name
  
$username// Mysql username
  
$password// Mysql password
  
$db_name// Database name
  
$tbl_name// Table name
$con mysql_connect($host$username$password)or die("cannot connect server ");

mysql_select_db("$db_name")or die("cannot select DB");

$sql="SELECT * FROM studentinfo" or die("cannot connect server ");

$result mysql_query($sql);
while(
$row mysql_fetch_array($result))
  {
    if (
$row['studnum'] == $q)
    {
    echo 
$row['fname'];
    }
  }
mysql_close($con); ?>
Thanks & God Bless